The mean and standard deviation of 100 observations were calculated as 40 and 5.1 respectively by a student who took by mistake 50 instead of 40 for one observation. What are the correct mean and standard deviation ?

A student obtained the mean and standard deviation of 100 observations as 40 and 5.1 respectively. It was later found that he had wrongly copied one observation as 50, the correct figure being 40. Calculate the correct mean and correct standard deviation.

The mean and standard deviation of two numbers are 10 and 2 respectively. Find the numbers.

The mean and standard deviation of a group of 100 observations were found to be 20 and 3, respectively. Later on it was found that three observations were incorrect, which were recorded as 21, 21 and 18. Find the mean and standard deviation if the incorrect observations are omitted.

The mean and standard deviation of six observations are 8 and 4, respectively. If each observation is multiplied by 3, find the new mean and new standard deviation of the resulting observations

The mean and standard deviation of observations are 8 and 14 respectively. If each observation be multiplied by 3, the find the new and mean and new standard deviation of the resulting observation.

The mean and standart deviation of five observations x_1,x_2,x_3,x_4,x_5 and are 10 and 3 respectively, then variance of the observation x_1,x_2,x_3,x_4,x_5,-50 is equal to

The mean and the standard deviation of a characteristic of 100 items were found to be 60 and 10 respectively. At the time of calculations, two items were wrongly take as 5 and 45 instead of 30 and 20. Calculate the corrected mean and corrected standard deviation.

The arithmetic mean and standard deviation of 7 observations are respectively 8 and 16. If five of the observations are 2, 4, 10, 12 and 14 then find the values of the remaining two.

The arithmetic mean and standard deviation of 7 observations are respectively 8 and 4.If five of the observations are 2,4,10,12 and 14 then find the values of the remaining two