The value of `sin^(-1)(sin12)+cos^(-1)(cos12)=`

Explanation

`sin^-1(sin12)+cos^-1(cos12)`

Here, we have to convert `sin12` into a value from `-pi/2` to ` pi/2` and `cos12` into a value from `0` to `pi`.

We can write,

`sin^-1(sin12)+cos^-1(cos12) = sin^-1(sin(12-4pi))+cos^-1(cos(4pi-12))`

`=12-4pi+4pi-12 = 0`

`:. sin^-1(sin12)+cos^-1(cos12) =0`