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For the equation cos^(-1)x+cos^(-1)2x+pi...

For the equation `cos^(-1)x+cos^(-1)2x+pi=0` , the number of real solution is (A)1 (B) 2 (C) 0 (D) `oo`

A

1

B

2

C

0

D

`oo`

Text Solution

Verified by Experts

We have `cos^(-1) x + cos^(-1) (2x) = -pi`, which is not possible as `cos^(-1) x and cos^(-1) 2x` never take negative values
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