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The value of tan^(-1).(4)/(7) + tan^(-1)...

The value of `tan^(-1).(4)/(7) + tan^(-1).(4)/(19) + tan^(-1).(4)/(39) + tan^(-1).(4)/(67) ... oo` equals

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The value of tan cot^(-1)(-4/3) is

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The value of ("sin"^(-1)(4)/(5)+2"tan"^(-1)(1)/(3)) is -

2 tan ^(-1) ""(1)/(5)+tan^(-1)"" (1)/(8)= tan ^(-1) ""(4)/(7)

Find the value of 4tan^(-1)(1/5)-tan^(-1)(1/(70))+tan^(-1)(1/(99))

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2 ( tan ^(-1)""(1)/(4) +tan ^(-1)""(2)/(9))=cos ^(-1)""(3)/(5)

Prove that, tan^(-1) (4/3) + tan^(-1) (12/5) = pi - tan^(-1)(56/33) .

CENGAGE PUBLICATION-INVERSE TRIGONOMETRIC FUNCTIONS-All Questions
  1. tan(pi/4+1/2cos^(-1)x)+tan(pi/4-1/2cos^(-1)x),x!=0, is equal to x (b)...

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  2. The sum of series sec^(-1) sqrt2 + sec^(-1).(sqrt10)/(3) + sec^(-1).(s...

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  3. The value of tan^(-1).(4)/(7) + tan^(-1).(4)/(19) + tan^(-1).(4)/(39) ...

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  4. If 3sin^(-1)((2x)/(1+x^2))-4cos^(-1)((1-x^2)/(1+x^2))+2tan^(-1)((2x)/(...

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  5. If sin^(-1)((2a)/(1+a^2))+sin^(-1)((2b)/(1+b^2))=2tan^(-1)x , then x ...

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  6. If alpha=tan^(-1)((4x-4x^3)/(1-6x^2+x^4)),beta=2sin^(-1)((2x)/(1+x^2))...

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  7. Absolute value of sum of all integers in the domain of f(x)=cot^(-1)sq...

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  8. Solve the equation tan^(-1)2x+tan^(-1)3x=pi/4

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  9. Solve tan^(-1)x+sin^(-1)x=tan^(-1)2xdot

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  10. 2"tan"(tan^(-1)(x)+tan^(-1)(x^3)),where x in R-{-1,1}, is equal to

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  11. If alpha=3sin^-1(6/(11)) and beta=3cos^-1(4/9), where the inverse trig...

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  12. Prove that: tan^(-1)x+tan^(-1)(1/x)={pi/2,ifx >0-pi/2,ifx<0

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  13. Find the value of sin^(-1)x+sin^(-1)(1/x)+cos^(-1)x+cos^(-1)(1/x)dot

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  14. Find the value of underset(r = 1)overset(10)sum underset(s = 1)overset...

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  15. If sin^(-1)xi in [0,1]AAi=1,2,3, .28 then find the maximum value of s...

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  16. Prove that cos^(-1)4/5 + cos^(-1)(12)/(13)=cos^(-1)(33)/(65)

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  17. If two angles of a triangle are tan^(-1)(2)a n dtan^(-1)(3), then find...

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  18. Find the sum of the following AP : 0.6, 1.7, 2.8, ……, to 100 terms.

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  19. Find the sum of the following AP -37, -33, -29, …… to 12 terms.

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  20. Let (x , y) be such that sin^(-1)(a x)+cos^(-1)(y)+cos^(-1)(b x y)=pi/...

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