Solve `sin^(-1)x+sin^(-1)2x=pi/3dot`

Explanation

`sin^-1x + sin^-1(2x) = pi/3`

`=>sin^-1(2x) = pi/3 - sin^-1x`

`=>sin^-1(2x) = sin^-1(sqrt3/2) - sin^-1x`

`=>sin^-1(2x) = sin^-1[sqrt3/2sqrt(1-x^2) - xsqrt(1-3/4)]`

`=>sin^-1(2x) = sin^-1[sqrt3/2sqrt(1-x^2) - x/2)]`

`=>2x = sqrt3/2sqrt(1-x^2) - x/2`

`=>(5x)/2 = sqrt3/2sqrt(1-x^2)`

Squaring both sides,

...