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Show that if x1, x2, x3!=0 abs((x1+a1....

Show that if `x_1, x_2, x_3!=0`
`abs((x_1+a_1.b_1,a_1.b_2,a_1.b_3),(a_2.b_1,x_2+a_2.b_2,a_2.b_3),(a_3.b_1,a_3.b_2,x_3+a_3.b_3))=x_1x_2x_3(1+(a_1b_1)/(x_1)+(a_2b_2)/(x_2)+(a_3b_3)/(x_3))` .

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