Evaluate`intcos2theta log((costheta+sintheta)/(costheta-sintheta))d theta`

Evaluate: intcos 2 theta ln((cos theta+sin theta)/(cos theta-sin theta))d theta

Prove that (sin 3theta-sintheta)/(costheta-cos3 theta)=cot2 theta

Evalute : |{:(cos^2 theta,costhetasintheta,-sintheta),(costhetasintheta,sin^2theta,costheta),(sintheta,-costheta,0):}|

The solution of the equation |(costheta,sintheta,costheta),(-sintheta,costheta,sintheta),(-costheta, -sintheta,costheta)|=0 is -

(1+sintheta-costheta)/(1+sintheta+costheta) =

If f(theta)=|{:(cos^2theta,costhetasintheta,-sintheta),(costhetasintheta,sin^2theta,costheta),(sintheta,-costheta," "0):}| , then find the value of f((pi)/6) .

Solve theta for 4sinthetacostheta=1+2costheta-2sintheta (0

Prove that all lines represented by the equation (2costheta+3sintheta)x+(3costheta-5sintheta)y=5costheta-2sintheta …(1) pass through a fixed point and its reflection in the line x+y=sqrt2 ? Prove that all lines through reflection point can be represented by the equation (2costheta+3sintheta)x+(3costheta-5sintheta)y= (sqrt2-1)(5costheta-2sintheta) ....(2)

If x=(2sintheta)/(1+costheta+sintheta),t h e n(1-costheta+sintheta)/(1+sintheta) is equal to

Simplify costheta[(costheta,sin theta),(-sintheta,costheta)]+sin[(sintheta,-costheta),(costheta,sintheta)]