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Evaluate: int(-pi/4)^(npi-pi/4)|sinx+cos...

Evaluate: `int_(-pi/4)^(npi-pi/4)|sinx+cosx|dx`

Text Solution

Verified by Experts

`I=int_(-pi//4)^(npi-pi//4)|sinx+cosx|dx`
`=int_(-pi//4)^(npi-(pi)/4) sqrt(2)|sin(x+pi//4)|dx`
(Multiplying and dividing by `sqrt(2)`)
`=nint_(0)^(pi)sqrt(2)|sin(x+pi//4)|dx`
[As `|sin(x+pi//4)|` is periodic with period `pi`]
`=sqrt(2)n[int_(0)^(3pi//4)sin(x+pi//4)dx+int_(3pi//4)^(pi)-sin(x+pi//4)dx]`
`=2sqrt(2)n`
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