Find the points where line `(x-1)/2=(y+2)/(-1)=z/1` intersects `x y ,y za n dz x` planes.

The coordinates of the point where the line (x-3)/(1)=(y-4)/(2)=(z-5)/(2) meets the plane x+y+z=17 are -

Perpendiculars are drawn from points on the line (x+2)/2=(y+1)/(-1)=z/3 to the plane x + y + z=3 The feet of perpendiculars lie on the line (a) x/5=(y-1)/8=(z-2)/(-13) (b) x/2=(y-1)/3=(z-2)/(-5) (c) x/4=(y-1)/3=(z-2)/(-7) (d) x/2=(y-1)/(-7)=(z-2)/5

Find the equation of the projection of the line (x-1)/(2)=(y+1)/(-1)=(z-3)/(4) on the plane x+2y+z=9 .

Perpendiculars are drawn from points on the line (x + 2)/(2) = (y +1)/(-1) = (z)/(3) to the plane x + y + z = 3 . The feet of perpendiculars lie on the line

Find the angle between the line (x-1)/3=(y-1)/2=(z-1)/4 and the plane 2x+y-3z+4=0.

The distance between the point (-1, -5, -10) and the point of intersection of the line (x-2)/(3)=(y+1)/(4)=(z-2)/(12) with the plane x-y+z=5 is -

The angle between the line (x-1)/(2)=(y-2)/(1)=(z+3)/(-1) and the plane x+y+4=0 is __

Find the angle between the line (x-1)/(3)=(y+1)/(2)=(z+2)/(4) and the plane 2x+y-3z+4=0 .

Find the distance of the point (-1,-5,-10) from the point of intersection of the line (x-2)/3=(y+1)/4=(z-2)/(12) and plane x-y+z=5.

If the lines (x-1)/2=(y+1)/3=(z-1)/4a n d(x-3)/1=(y-k)/2=z/1 intersect, then find the value of kdot