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Solve (log)2(3x-2)=(log)(1/2)x...

Solve `(log)_2(3x-2)=(log)_(1/2)x`

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`log_(2)(3x-2)=log_(1//2)x=-log_(2)x=log_(2)x^(-1)`
`or3x-2=x^(-1)or3x^(2)-2x=1`
`rArrx=1orx=-1//3`.
But `log_(2)(3x-2)` and `log_(1//2)x` are meaningful if `xgt2//3`. Hence, x=1
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