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Solve 2^(x+2)27^(x//(x-1))=9...

Solve `2^(x+2)27^(x//(x-1))=9`

Text Solution

Verified by Experts

Taking log of both sides, we get
`(x+2)log2+(x)/(x-1)log27=log9`
`or(x+2)log2+(x)/(x-1)3log3=2log3`
`or(x+2)log2+((3x)/(x-1)-2)log3=0`
or `(x+2)[log2+(log3)/(x-1)]=0`
`rArrx=-2orx-1=-(log3)/(log2)`
`rArrx=-2,1-(log3)/(log2)`
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