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Find the angle between the lines 2x=3y...

Find the angle between the lines `2x=3y=-z` and `6x=-y=-4z`

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The lines are `(x)/(3)=(y)/(2)=(z)/(-6) and (x)/(2)=(y)/(-12) = (z)/(-3)`.
Since `a_(1)a_(2)+b_(1)b_(2)+c_(1)c_(2)=6-24+18=0`, we have
`" "theta=90^(@)`
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