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If the lines (x-1)/(-3)=(y-2)/(2k)=(z-3)...

If the lines `(x-1)/(-3)=(y-2)/(2k)=(z-3)/(-2)` and `(x-1)/(3k)=(y-5)/1=(z-6)/(-5)` are at right angle, then find the value of `k`.

Text Solution

Verified by Experts

The lines are perpendicular if `a_(1)a_(2)+b_(1)b_(2)+c_(1)c_(2)=0`.
Hence, `-3(3k)+2k(1)+2(-5)=0 or k=-(10)/(7)`.
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