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Evaluate: lim(x->oo)[x(a^(1/x)-1)], a >1...

Evaluate: `lim_(x->oo)[x(a^(1/x)-1)], a >1`

Text Solution

Verified by Experts

The correct Answer is:
`log_(e)a`
`underset(xtooo)limx(a^(1//x)-1)=underset(xtooo)lim[(a^(1//x)-1)/(1//x)]=log_(e)a`
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