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Evaluate underset(xtooo)lim(sinx)/(x)....

Evaluate `underset(xtooo)lim(sinx)/(x).`

Text Solution

Verified by Experts

The correct Answer is:
`pi//180`
`underset(xto0)lim(sinx^(@))/(x)=underset(xto0)lim("sin"(pix)/(180))/(x)=(pi)/(180)" "{becausex^(@)=(pix)/(180)" radian"}`
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