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lim(xtoa) (log(x-a))/(log(e^(x)-e^(a)))...

`lim_(xtoa) (log(x-a))/(log(e^(x)-e^(a)))`

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Verified by Experts

The correct Answer is:
1
`underset(xtoa)lim(log(x-a))/(log(e^(x)-a^(a)))`
`=underset(xtoa)lim((1)/(x-a))/(e^(x)/(e^(x)-e^(a)))" "`(Applying L'Hospital's rule)
`=underset(xtoa)lim(e^(x)-e^(a))/(e^(x)(x-a))`
`=underset(xtoa)lim(e^(a)(e^(x-a)-1))/(e^(x)(x-a))`
=1
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