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A(1,3) and C(-2,/5, -2/5) are the vertic...

A(1,3) and C(-2,/5, -2/5) are the vertices of a triangle ABC and the equation of the internal angle bisector of `angleABC " is " x+y=2.`
The coordinates of vertex B are

A

7x+3y-4=0

B

7x+3y+4=0

C

7x-3y+4=0

D

7x-3y-4=0

Text Solution

Verified by Experts

The correct Answer is:
B
The image of A(1,3) in line x+y=2 is
`(1-2(2)//2,3-2(2)//2)-=(-1, 1)`
So, line BC passes through (-1, 1) and (-2/5, -2/5). The equation of line BC is

`y-1 = (-2//5-1)/(-2//5+1)(x+1)`
or 7x+3y+4=0
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