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Draw the graph of y=sec^(-1)x+cosec^(-1)...

Draw the graph of `y=sec^(-1)x+cosec^(-1)x`

Text Solution

Verified by Experts

We have `y=f(x) =sec^(-1)x+cosec^(-1)x, x in (-oo, -1]cup [1, oo)`
`=pi/2`
`"So the graph of "y=f(x) "is the line "y=pi/2" for "x in (-oo, -1]cup[1, oo)`
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