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Find the value of x for which sec^(-1)xs...

Find the value of `x` for which `sec^(-1)xsin^(-1)x=pi/2dot`

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We know that `sec^(-1) x` is defined for `x in (-oo, -1] uu [1, oo)`. But `sin^(-1) x` is defined for `x in [-1, 1]`
Hence, `sec^(-1) x + sin^(-1) x = (pi)/(2) " for " x = +- 1`
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CENGAGE PUBLICATION-INVERSE TRIGONOMETRIC FUNCTIONS-All Questions
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