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If x in [-1,0], then find the value of c...

If `x in [-1,0],` then find the value of `cos^(-1)(2x^2-1)-2sin^(-1)x`

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The correct Answer is:
`pi`
`cos^(-1) (2x^(2) -1) = 2pi - 2 cos^(-1) x " " ("as " x lt 0)`
`rArr cos^(-1) (2x^(2) -1) -2 sin^(-1) x = 2pi - 2 cos^(-1) x - 2sin^(-1) x`
`= 2pi - 2 (cos^(-1) x + sin^(-1) x)`
`= 2pi - 2 (pi)/(2) = pi`
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CENGAGE PUBLICATION-INVERSE TRIGONOMETRIC FUNCTIONS-All Questions
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  2. If x in (0, 1), then find the value of tan^(-1) ((1 -x^(2))/(2x)) + co...

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  3. If x in [-1,0], then find the value of cos^(-1)(2x^2-1)-2sin^(-1)x

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