If `x=sin^(-1)(a^6+1)+cos^(-1)(a^4+1)-tan^(-1)(a^2+1),a in R ,` then the value of `sec^2x` is_______

Answer

2

Explanation

Since `sin^(-1)` is defined for `[-1, 1]` so we have `a = 0`
`:. X = sin^(-1) 1 + cos^(-1) 1 - tan^(-1) 1 = (pi)/(4)`
`rArr sec^(2) x = 2`