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A rectangle A B C D , where A-=(0,0),B-=...

A rectangle `A B C D ,` where `A-=(0,0),B-=(4,0),C-=(4,2)D-=(0,2)` , undergoes the following transformations successively:
`f_1(x ,y)to(y ,x)`
`f_2(x , y)to(x+3y ,y)`
`f_3(x , y)to((x-y)/2),(x+y)/2)`
The final figure will be
(a) square
(b) a rhombus
(c) a rectangle
(d) a parallelogram

A

a square

B

a rhombus

C

a rectangle

D

a parallelogram

Text Solution

Verified by Experts

The correct Answer is:
D

Clearly,A will remain as `(0,0),f_1` will make B as (0,4) , `f_2` will make it `(12,4)` , and `f_3` will make it `(4,8),f_1` will make C as `(2,4),f_2` will make it (14,4) and `f_3` will make it (5,9). Finally, `f_1` will make D as (2,0) `f_2` will make it (2,0) and `f_3` will make it (1,1) so, we finally get `A-=(0,0),B-=(4,8), C-=(5,9)` , and `D-=(1,1)`. Hence,
`m_(AB)=(8)/(4)m_(BC)=(9-8)/(5-4)=1, m_(CD)=(9-1)/(5-1)=(8)/(4)`,
`m_(AD)=1,m_(BC)=(9)/(5), m_(CD)=(8-1)/(4-1)=(7)/(3)`,
Hence, the final figure will be a parallelogram.
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