Home
Class 12
MATHS
The foot of the perpendicular on the lin...

The foot of the perpendicular on the line `3x+y=lambda` drawn from the origin is `Cdot` If the line cuts the `x` and the y-axis at `Aa n dB` , respectively, then `B C: C A` is

A

`1:3`

B

`3:1`

C

`1:9`

D

`9:1`

Text Solution

Verified by Experts

The correct Answer is:
D

`tan180^@-theta)=`Slope of `AB=-3`
`thereforetan theta=3`
`therefore(OC)/(AC)=tantheta,(OC)/(BC)=cottheta`
or `(BC)/(AC)=(tantheta)/(cottheta)=tan^2theta=9`
Promotional Banner

Topper's Solved these Questions

  • COORDINATE SYSYEM

    CENGAGE PUBLICATION|Exercise Multiple correct|13 Videos
  • COORDINATE SYSYEM

    CENGAGE PUBLICATION|Exercise Linked|10 Videos
  • COORDINATE SYSYEM

    CENGAGE PUBLICATION|Exercise Concept applications 1.6|9 Videos
  • COORDINATE SYSTEM

    CENGAGE PUBLICATION|Exercise Multiple Correct Answers Type|2 Videos
  • CROSS PRODUCTS

    CENGAGE PUBLICATION|Exercise DPP 2.2|13 Videos

Similar Questions

Explore conceptually related problems

The perpendicular distance of the starght line 3x+4y+15=0 from the origin is -

Prove that the perpendicular distance of the line 3x+4y+5 =0 from origin is 1 unit.

The perpendicular distance of the straight line 3x + 4y + 15 = 0 from the origin, is

The perpendicular distance of the starght line 3x+4y+m=0 from the origin is 2 unit , find m.

State which of the following is the perpendicular distance of the line 3x-4y-5=0 from the origin ?

The distance of the straight line a(x-a)+b(y-b)=0 from the origin is -

Find the equation of the line perpendicular to the line x/a-y/b=1 and passing through a point at which it cuts the x-axis.

Find the locus of the foot of the perpendicular drawn from the origin to the straight line which passes through the fixed point (a,b).

Find the equation of a line drawn perpendicular to the line x/4 + y/6 = 1 through the point , where it meets the y-axis.

The co-ordinates of the foot of perpendicular from (a, 0) on the line y=mx+(a)/(m) are

CENGAGE PUBLICATION-COORDINATE SYSYEM -Exercises
  1. Point A and B are in the first quadrant,point O is the origin. If the ...

    Text Solution

    |

  2. Let a,b,c be in A.P and x,y,z be in G.P.. Then the points (a,x),(b,y) ...

    Text Solution

    |

  3. If sum(i=1)^4(x1^2+y 1^2)lt=2x1x3+2x2x4+2y2y3+2y1y4, the points (x1, y...

    Text Solution

    |

  4. The vertices A and D of square A B C D lie on the positive sides of x-...

    Text Solution

    |

  5. Through the point P(alpha,beta) , where alphabeta>0, the straight line...

    Text Solution

    |

  6. The locus of the moving point whose coordinates are given by (e^t-e^(-...

    Text Solution

    |

  7. The locus of a point reprersented by x=a/2((t+1)/t),y=a/2((t-1)/t) , w...

    Text Solution

    |

  8. Vertices of a variable triangle are A(3,4),B(5costheta, 5sintheta) and...

    Text Solution

    |

  9. Vertices of a variable triangle are A(3,4),B(5costheta, 5sintheta) and...

    Text Solution

    |

  10. From a point, P perpendicular PM and PN are drawn to x and y axis, res...

    Text Solution

    |

  11. The locus of point of intersection of the lines y+mx=sqrt(a^2m^2+b^2) ...

    Text Solution

    |

  12. If the roots of the equation (x(1)^(2)-a^2)m^2-2x1y1m+y(1)^(2)+b^2=0...

    Text Solution

    |

  13. Through point P(-1,4), two perpendicular lines are drawn which interse...

    Text Solution

    |

  14. The number of integral points (x,y) (i.e, x and y both are integers) w...

    Text Solution

    |

  15. The foot of the perpendicular on the line 3x+y=lambda drawn from the o...

    Text Solution

    |

  16. The image of P(a,b) on the line y=-x is Q and the image of Q on the li...

    Text Solution

    |

  17. If the equation of the locus of a point equidistant from the points (a...

    Text Solution

    |

  18. Consider three lines as follows. L1:5x-y+4=0 L2:3x-y+5=0 L3: x+y+8=0...

    Text Solution

    |

  19. Consider a point A(m,n) , where m and n are positve intergers. B is th...

    Text Solution

    |

  20. In the given figure, OABC is a rectangle. Slope of OB is

    Text Solution

    |