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For points P=(x1,y1)and Q =(x2,y2) of th...

For points `P=(x_1,y_1)`and `Q =(x_2,y_2)` of the co-ordinate plane a new distance d(P,Q)=`|x_1-x_2|+|y_1-y_2|` is defined .Let O(0,0)and A(3,2). The set of points in first quadrant which are equidistant from O and A is

A

one -one and onto function

B

many one and onto function

C

one-one and into function

D

relation but not function

Text Solution

Verified by Experts

The correct Answer is:
D

Obviously, the locus of P is a relation but not a function.
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