Home
Class 12
MATHS
The sum of coefficient of integral power...

The sum of coefficient of integral powers of x in the binomial expansion of `(1-2sqrtx)^50` is:

A

`1/2(3^(50) + 1)`

B

`1/2(3^(50))`

C

`1/2(3^(50) - 1)`

D

`1/2(2^(10) + 1)`

Text Solution

Verified by Experts

The correct Answer is:
A

`(1-2sqrt(x))^(50) = C_(0)-C_(1)2sqrt(x)+C_(2)(2sqrt(x))^(2)-"...."+C_(50)+(2sqrt(x))^(50)`
`(1+2sqrt(x))^(50) = C_(0) + C_(1)(2sqrt(x))+C_(2)(2sqrt(x))^(2) + "......" + C_(50)(2sqrt(x))^(50)`
Putting `x = 1`, we get
`:. (3^(50)+1)/(2)= C_(0) + C_(2)(2)^(2) + "...."`
Promotional Banner

Topper's Solved these Questions

  • BINOMIAL THEOREM

    CENGAGE PUBLICATION|Exercise Multiple Correct Answer|4 Videos
  • BINOMIAL THEOREM

    CENGAGE PUBLICATION|Exercise Comprehension|11 Videos
  • BINOMIAL THEOREM

    CENGAGE PUBLICATION|Exercise Numerical|25 Videos
  • AREA

    CENGAGE PUBLICATION|Exercise Comprehension Type|2 Videos
  • CIRCLE

    CENGAGE PUBLICATION|Exercise For problems 3 and 4|2 Videos

Similar Questions

Explore conceptually related problems

The sum pf coefficients of integral powers of x is the binomial expansion (1-2sqrt(x))^(50) is -

The sum of the coefficients of all the integral powers of x in the expansion of (1+2sqrtx)^(40) is

The sum of the coefficients of even power of x in the expansion of (1+x+x^2+x^3)^5 i s 256 b. 128 c. 512 d. 64

The sum of the coefficients of the terms of the expansion of (3x-2y)^n is

Show that the sum of the coefficients of the odd terms in the expansion of (1+x)^(2n)" is "2^(2n-1)

Show that the sum of the coefficients of all odd terms in the expansion of (1+x)^(2p) is 2^(2p-1) .

The coefficient of the middle term of the expansion of (1-2x+x^2)^n is

prove that the coefficient of the (r +1)th term in the expansion of (1+x)^(n) is equal to the sum of the coefficients of the rth and (r+1)th terms in the expansion of (1+x)^(n-1)

The coefficient of x^3 in the expansion of (1-x+x^2)^5 is

Show that the sum of the coefficient of first (r+1) terms in the expansions of (1-x)^(-n) is ((n+1)(n+2)...(n+r))/(r!)