If y=x+e^x, then (d^2x)/(dy^2) is (a) ...

If `y=x+e^x,` then `(d^2x)/(dy^2)` is

(a) `e^x`

(b) `- e^x/((1+e^x)^3)`

(c) `-e^x/((1+e^x)^2)`

(d) `(-1)/((1+e^x)^3)`

A

`(-sin x +e^(x))^(-1)`

B

`(sin x - e^(x))/((cos x +e^(x))^(2))`

C

`(sin x - e^(x))/((cos x +e^(x))^(3))`

D

`(sin x + e^(x))/((cos x +e^(x))^(3))`

Text Solution

Verified by Experts

`y=sin x +e^(x)or (dy)/(dx)=cos x +e^(x)`
`"or "(dx)/(dy)=(cos x +e^(x))^(-1)" (1)"`
`therefore" "(d^(2)x)/(dy^(2))=-(cos x +e^(x))^(-2)(-sin x +e^(x))(dx)/(dy)`
Substituting the value of `(dy)/(dx)` from (1),
`(d^(2)x)/(dy^(2))=((sin x -e^(x)))/((cos x +e^(x))^(2))(cos x +e^(x))^(-1)=(sin x-e^(x))/((cos x +e^(x))^(3))`

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