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If x = log p and y=(1)/(p), then...

If x = log p and `y=(1)/(p),` then

A

`(d^(2)y)/(dx^(2))-2p=0`

B

`(d^(2)y)/(dx^(2))+y=0`

C

`(d^(2)y)/(dx^(2))+(dy)/(dx)=0`

D

`(d^(2)y)/(dx^(2))-(dy)/(dx)=0`

Text Solution

Verified by Experts

`(dy)/(dx)=(-(1)/(p^(2)))/((1)/p)=-(1)/(p)=-y`
`"or "(d^(2)y)/(dx^(2))=-(dy)/(dx)`
`"or "(d^(2)y)/(dx^(2))+(dy)/(dx)=0`
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