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If x^3+y^3-3axy=0,then dy/dx equals...

If `x^3+y^3-3axy`=0,then `dy/dx` equals

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`x=f(t)=a^(In(b^t))=a^(t" In "b)" (1)"`
`y=g(t)=b^(-In(a^(t)))=(b^(In a))^(-t)=(a^(In b))^(-t)=a^(-t" In b")`
`therefore" "y=g(t)=a^(In(b^(-t)))=f(-t)" (2)"`
From equations (1), and (2),
`xy=1`
`f(t)=g(t)rArrf(t)=f(-t)rArrt=0" "[because f(t)" is one-one function"]`
`"At "t=0, x=y=1`
`because" "xy=1, (dy)/(dx)=(-1)/(x^(2))and (d^(2)y)/(dx^(2))=(2)/(x^(3))" At "x=1, (d^(2)y)/(dx^(2))=2`
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