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y=x is tangent to the parabola y=ax^(2)+...

y=x is tangent to the parabola `y=ax^(2)+c`.
If c=2, then the point of contact is

A

A. (3,3)

B

B. (2,2)

C

C. (6,6)

D

D. (4,4)

Text Solution

Verified by Experts

The correct Answer is:
D

(4) If c=2, then the point of contact is `(1//2a,1//4a+2)`.
Since it lies on the line y=x, we have
`(1)/(2a),(1)/(4a)+2`
`i.e," "a=(1)/(8)`
Therefore, the point of contact is (4,4)
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