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vecrxxveca=vecbxxveca,vecrxxvecb=vecaxxv...

`vecrxxveca=vecbxxveca,vecrxxvecb=vecaxxvecb,vecanevec0,vecbnevec0,vecanelambdavecb and veca` is not perpendicular to `vecb`, then find `vecr` in terms of `veca and vecb`.

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`vecrxxveca-vecbxxveca=0andvecrxxvecb+vecbxxveca=0`
Adding , wer get `vecrxx(veca+vecb)=0`
But as we are given `veca ne lambda vecb` . Therefore
`vecr=mu ( veca+vecb)`
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