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Tangent to the parabola y=x^(2)+ax+1 at ...

Tangent to the parabola `y=x^(2)+ax+1` at the point of intersection of the y-axis also touches the circle `x^(2)+y^(2)=r^(2)`. Also, no point of the parabola is below the x-axis.
The slope of the tangents when the radius of the circle is maximum is

A

(a) -1

B

(b) 1

C

(c) 0

D

(d) 2

Text Solution

Verified by Experts

The correct Answer is:
C

(3) The equation of the tangent at (0,1) to the parabola
`y=x^(2)+ax+1` is
y-1=a(x-0)
`orax-y+1=0`
As it touches the circle, we get
`r=(1)/(sqrt(a^(2)+1))`
The radius is maximum when a=0.
Therefore, the equation of the tangent is y=1.
Therefore, the slope of the tangent is 0.
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