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Evaluate: inte^x\ (logx+1/(x^2))\ dx...

Evaluate: `inte^x\ (logx+1/(x^2))\ dx`

Text Solution

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`I=int e^(x)(log x+(1)/(x^(2)))dx=int e^(x)((log x-(1)/(x))+((1)/(x)+(1)/(x^(2))))dx`
`=e^(x)(log x-(1)/(x))+c " "[ :' (d)/(dx)(log x-(1)/(x))=(1)/(x)+(1)/(x^(2))]`
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