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Evaluate: int{1+tanxtan(x+theta)}\ dx...

Evaluate: `int{1+tanxtan(x+theta)}\ dx`

Text Solution

Verified by Experts

The correct Answer is:
`log_(e)|4sin^(2)x-1|+C`
`int(sin2x)/("sin"^(2)x-"sin"^(2)(pi)/(6))dx=int(("sin"^(2)x-"sin"^(2)(pi)/(6))^('))/("sin"^(2)x-"sin"^(2)(pi)/(6))dx`
`=log_(e)|"sin"^(2)x-(1)/(4)|+C`
`=log_(e)|4sin^(2)x-1|+C`
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