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int(cos e c^2x-2005)/(cos^(2005)x)dx is ...

`int(cos e c^2x-2005)/(cos^(2005)x)dx` is equal to (a) `-(cotx)/((cosx)^(2005))+c` (b) `(tanx)/((cosx)^(2005))+c` (c) `-(tanx)/((cosx)^(2005)+c` (d) none of these

A

`(cotx)/((cosx)^(2005))+c`

B

`(tan x)/((cosx)^(2005))+c`

C

`(-(tan x))/((cosx)^(2005))+c`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
D

`int("cosec"^(2)x-2005)/(cos^(2005)x)dx`
`=int(cotx)^(-2005)"cosec"^(2)xdx-2005 int (dx)/(cos^(2005)x)`
`=(cosx)^(-2005)(-cot x)-int (-2005)(cosx)^(-2006)(-sinx)(-cotx)dx-2005int(dx)/(cos^(2005)x)`
`= -(cotx)/((cosx)^(2005))+C`
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