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Let the angles A , Ba n dC of triangle A...

Let the angles `A , Ba n dC` of triangle `A B C` be in `AdotPdot` and let `b : c` be `sqrt(3):sqrt(2)` . Find angle `Adot`

Text Solution

Verified by Experts

The correct Answer is:
`(5pi)/(12)`
Angles are in A.P., so, `B = (pi)/(3)`
Also, `(b)/(c) = (sqrt3)/(sqrt2) " or " (b)/(sqrt3) = (c)/(sqrt2) " or " (b)/((sqrt3)/(2)) = (c)/((1)/(sqrt2))`
But we know that `(b)/(sin B) = (c)/(sin C) = (a)/(sin A)`
`:. B = (pi)/(3), C = (pi)/(4) rArr A = (5pi)/(12)`
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