If two sides of a triangle are roots of the equation `x^2-7x+8=0` and the angle between these sides is `60^0` then the product of inradius and circumradius of the triangle is `8/7` (b) `5/3` (c) `(5sqrt(2))/3` (d) `8`

Options

A. `(8)/(7)`
B. `(5)/(3)`
C. `(5sqrt2)/(3)`
D. 8

Answer

B

Explanation

Let a and b the roots of `x^(2) -7 x + 8 = 0`
Then `a + b = 7, ab = 8`
Also, `C = 60^(@)`
`rArr c^(2) = a^(2) + b^(2) - ab`
`rArr c^(2) = (a +b)^(2) -3ab = 49 -24 = 25`
`rArr c = 5`
`:. r.R = (abc)/(2(a+b+c)) = (8xx5)/(2(7+5)) = (5)/(3)`