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Let G be the centroid of triangle ABC an...

Let G be the centroid of triangle ABC and the circumcircle of triangle AGC touches the side AB at A
If AC = 1, then the length of the median of triangle ABC through the vertex A is equal to

A

`(sqrt3)/(2)`

B

`(1)/(2)`

C

`(2)/(sqrt3)`

D

`(5)/(sqrt2)`

Text Solution

Verified by Experts

The correct Answer is:
A
We have `AD = sqrt((2b^(2) + 2c^(2) -a^(2))/(4)) = (sqrt3b)/(2)`
If `b = 1 " then " AD = (sqrt3)/(2)`
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