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If sectheta+tantheta=p. Then find the va...

If `sectheta+tantheta=p`. Then find the value of `tantheta`.

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The correct Answer is:
`(p^2-1)/(2p)`

`sectheta+tantheta=p`
`rArr sectheta-tantheta=1/p`
subtracting second from first, we get
`2 tantheta =p -1/por tantheta =(p^2-1)/(2p)`
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