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Find the value of cot54^@/(tan36^@)+tan2...

Find the value of `cot54^@/(tan36^@)+tan20^@/(cot70^@)`

Text Solution

Verified by Experts

The correct Answer is:
2
`cot54^@/(tan36^@)+tan20^@/(cot70^@)=(cot(90^@-36^@))/(tan36^@)+(cot(90^@-70^@))/(cot70^@)`
`=tan36^@/(tan36^@)+cot70^@/(cot70^@)=2`
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  • The value of tan 15^@ tan 20^@ tan 70^@ tan 75^@ is

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