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If alphaa n dbeta,alphaa n dgamma,alphaa...

If `alphaa n dbeta,alphaa n dgamma,alphaa n ddelta` are the roots of the equations `a x^2+2b x+c=0,2b x^2+c x+a=0a d nc x^2+a x+2b=0,` respectively, where a, b, and c are positive real numbers, then `alpha+alpha^2=` `a b c` b. `a+2b+c` c. `-1` d. `0`

A

`-1`

B

`1`

C

`0`

D

`abc`

Text Solution

Verified by Experts

The correct Answer is:
A

`(a)` `alpha` is root of all equations.
`:.a alpha^(2)+2balpha+c=0`
`2balpha^(2)+calpha+a=0`
`calpha^(2)+aalpha+2b=0`
Adding `(a+2b+c)(1+alpha+alpha^(2))=0`
As `a`,`b`,`c in R^(+)`, `alpha+alpha^(2)=-1`
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