If the roots of x^(4)+qx^(2)+kx+225=0 ar...

If the roots of `x^(4)+qx^(2)+kx+225=0` are in arthmetic progression, then the value of `q`, is

A

`15`

B

`25`

C

`35`

D

`-50`

Text Solution

Verified by Experts

The correct Answer is:

D

`(d)` Let the `4` roots be `x-3y`, `x-y`, `x+y`, `x+3y`
`"sum"=4x` and if `4x=0` then `4` roots are `-3y`, `-y`, `y`,`3y` and the product is `9y^(4)=225impliesy^(2)=5`.
The product taken two at a time is `-10y^(2)`
`implies q=-50`

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