Home
Class 12
MATHS
Suppose n is a natural number such that ...

Suppose n is a natural number such that `|i + 2i^2 + 3i^3 +...... + ni^n|=18sqrt2` where `i` is the square root of `-1`. Then n is

A

`9`

B

`18`

C

`36`

D

`72`

Text Solution

Verified by Experts

The correct Answer is:
C

`(c )` `S=i+2i^(2)+3i^(3)+…….+ni^(n)`………..`(i)`
`:. iS=i^(2)+2i^(3)+3i^(4)+…….+ni^(n-1)`…………`(ii)`
Subtracting, we get ,brgt `S(1-i)=i+i^(2)+i^(3)+………..+i^(n)-ni^(n+1)`
`=(i(1-i^(n)))/(1-i)-ni^(n+1)`
Now put the values of `n` and verify.
Promotional Banner

Topper's Solved these Questions

  • COMPLEX NUMBERS

    CENGAGE PUBLICATION|Exercise Multiple Correct Answer|11 Videos
  • COMPLEX NUMBERS

    CENGAGE PUBLICATION|Exercise Matching Column|1 Videos
  • CIRCLES

    CENGAGE PUBLICATION|Exercise Comprehension Type|8 Videos
  • CONIC SECTIONS

    CENGAGE PUBLICATION|Exercise All Questions|102 Videos

Similar Questions

Explore conceptually related problems

The square root of 2i is

If x=a+bi is a complex number such that x^2=3+4i and x^3=2+11i , where i=sqrt-1 , then (a+b) equal to

For n being a natural number prove that 1.1!+2.2!+3.3!+.....+n.n! =(n+1)!-1 by applying P.M.I

If nge3 is an integer prove that 2n+1 lt 2^n by P.M.I.

In a test , there were n number of question. In the test 2^(n - i) students gave wrong answers to i number of question , where i = 1, 2, 3,......, n. If the total number of wrong answer of wrong answer given is 2047, then n is

If the events E_1, E_2,………….E_n are independent and such that P(E_i^C) = i/(i+1) , i=1, 2,……n, then find the probability that at least one of the n events occur.

Find the least positive integer n such that ((2i)/(1+i))^n is a positive integer.

Value of i^n+i^(n+1)+i^(n+2)+i^(n+3) (where i=sqrt-1 )

If (4+sqrt(15))^n=I+f, where n is an odd natural number, I is an integer and ,then

A coin is tossed. If head appears a fair die is thrown three times otherwise a biased die with probability of obtaining an even number twice as that of an odd number is thrown three times. If (n_(1),n_(2),n_(3)) is an outcome, (1 le n_(1) le6) and is found to satisfy the equation i^(n_(1))+i^(n_(2))+i^(n_(3))=1 , , then the probability that a fair die was thrown is (where i=sqrt(-1))