A circle with center `(a , b)` passes through the origin. The equation of the tangent to the circle at the origin is (a)`a x-b y=0` (b) `a x+b y=0` `b x-a y=0` (d) `b x+a y=0`

Options

A. `ax-by=0`
B. `ax+by=0`
C. `bx-ay=0`
D. `bx+ay=0`

Answer

2

Explanation

Obviously , the slope of the tangent will be `((1)/(b//a)), i.e., -(a)/(b)`.
Hence, the equation of the tangent is `y= -(a)/(b)x, i.e., ` by `+ax =0`