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S straight line with slope 2 and y-intercept 5 touches the circle `x^2+y^2+16 x+12 y+c=0` at a point `Q` . Then the coordinates of `Q` are `(-6,11)` (b) `(-9,-13)` `(-10 ,-15)` (d) `(-6,-7)`

A

`(-6,11)`

B

`(-9,-13)`

C

`(-10,-15)`

D

`(-6,-7)`

Text Solution

Verified by Experts

The correct Answer is:
4

From the figure , we have
`y_(1)=2x_(1)+5`
`y_(1)+6`
and `(y_(1)+6)/(x_(1)+8)xx2= -1`
`x_(1)+2y_(1)+20=0`
`:. x_(1)= -6` and `y_(1)= -7`
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