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If the length of the common chord of two...

If the length of the common chord of two circles `x^2+y^2+8x+1=0` and `x^2+y^2+2muy-1=0` is `2sqrt(6)` , then the values of `mu` are `+-2` (b) `+-3` (c) `+-4` (d) none of these

A

`+-2`

B

`+-3`

C

`+-4`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
2
The common choard is `S_(1)-S_(2)=0`
`4x- mu y +1=0`
`:. AC =` Radius of first circle `=sqrt(15)`
`AM=(AB)/(2)=sqrt(6)`
`:. CM=3`
`:. (|-16+1|)/(sqrt(16+mu^(2)))=3`
or `mu = +-3`
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