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(r(2)+r(3))sqrt((r r(1))/(r(2)r(3)))=...

`(r_(2)+r_(3))sqrt((r r_(1))/(r_(2)r_(3)))=`

A

a

B

b

C

c

D

bc

Text Solution

Verified by Experts

The correct Answer is:
A
`r_(2)+r_(3)=4R"cos"^(2)(A)/(2)`
`(r r_(1))/(r_(2)r_(3))="tan"^(2)(A)/(2)`
`rArr (r_(2)+r_(3))sqrt((r r_(1))/(r_(2)r_(3)))`
`=4 R"cos"^(2)(A)/(2)xx "tan"(A)/(2)`
= 2R sin A
= a
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