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If (a^2-1)x^2+(a-1)x+a^2-4a+3=0 is ident...

If `(a^2-1)x^2+(a-1)x+a^2-4a+3=0` is identity in `x` , then find the value of `a` .

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The given relation is satisfied for all real values of x, so all the coefficients must be zero. Then,
`{:(a^(2)-1 = 0 rArr a = pm1),(a- 1 = 0 rArr a = 1),(a^(2)- 4a +3=0rArr a = 1","3 ):}}` common value of a is 1
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CENGAGE PUBLICATION-THEORY OF EQUATIONS-ILLUSTRATION
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