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Solve the equation 3x^(2-x)+4x^2=25....

Solve the equation `3x^(2-x)+4x^2=25.`

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We have,
`3^(x^(2)- x )+ 4 ^(x^(2) - x) = 25`
or ` `3^(x^(2)- x )+ 4 ^(x^(2) - x) = 3^(2) + 4^(2)`
`x^(2) -x = 2`
or `x^(2) - x - 2 = 0`
or `(x - 2) )(x + 1) = 0`
or x = -1, 2
Hence, the roots of the given equation are -1 and 2.
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