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If k + |k + z^2|=|z|^2(k in R^-), then ...

If `k + |k + z^2|=|z|^2(k in R^-)`, then possible argument of z is

A

0

B

`pi`

C

`pi//2`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
Given that `|k + z^(2)| = |z^(2)| - K = |z^(2)| + |k|`
`rArr k,z^(2) and 0 + i0` are collinear
`rArr arg(z^(2)) = arg(k)`
`rArr 2 arg (z) = pi`
` rArr arg(z) = (pi)/(2)`
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