Home
Class 12
MATHS
The value of the expression 1.(2-omega)....

The value of the expression `1.(2-omega).(2-omega^2)+2.(3-omega)(3-omega^2)+.+(n-1)(n-omega)(n-omega^2),` where omega is an imaginary cube root of unity, is………

Text Solution

Verified by Experts

`S=1xx(2-omega)xx(2-omega^(2))+2xx(3-omega)xx(3-omega)xx(3-omega^(2))+…+(n-1)xx(n-omega)xx(n-omega^(2))`
Here, `T_(n)=(n-1)xx(n-omega)xx(n-omega^(2))=n^(3)-1`
`thereforeS=sum_(n=2)^(n)(n^(3)-1)`
`=sum_(n=1)^(n)(n^(3)-1)`
`=(n^(2)(n+1)^(2))/4-n`
`=(n^(2)(n^(2)+2n+1)-4n)/4`
`1/4n(n^(3)+2n^(2)+n-4)`
`=1/2n(n-1)(n^(2)+3n+4)`
Promotional Banner

Topper's Solved these Questions

  • PROGRESSION AND SERIES

    CENGAGE PUBLICATION|Exercise SOLVED EXAMPLES 5.8|1 Videos
  • PROGRESSION AND SERIES

    CENGAGE PUBLICATION|Exercise SOLVED EXAMPLES 5.9|1 Videos
  • PROGRESSION AND SERIES

    CENGAGE PUBLICATION|Exercise SOLVED EXAMPLES 5.6|1 Videos
  • PROBABILITY II

    CENGAGE PUBLICATION|Exercise MULTIPLE CORRECT ANSWER TYPE|6 Videos
  • PROPERTIES AND SOLUTIONS OF TRIANGLE

    CENGAGE PUBLICATION|Exercise Archives (Numerical Value Type)|3 Videos

Similar Questions

Explore conceptually related problems

|{:(1,omega,omega^2),(omega,omega^2,1),(omega^2,1,omega):}|=0 where omega is an imaginary cube root of unity.

Evaluate abs((1,omega,omega^2),(omega^2,1,omega),(omega^2,omega,1)) were omega is an imaginary cube root of unity.

Evalute: |{:(1,omega^3,omega^2),(omega^3,1,omega),(omega^2,omega,1):}| , where omega is an imaginary cube root of unity .

Evaluate: |{:(1,1,1),(1,omega^2,omega),(1,omega,omega^2):}| (where omega is an imaginary cube root of unity ).

The sum of the series 2(omega+1)(omega^2+1)+3(2omega+1)(2omega^2+1)+ 4(3omega+1)(3omega^2+1)+ ...n terms is

The condition satisfied by omega the imaginary ,cube root of unity is

The value of (1-omega+omega^(2))^(5)+(1+omega-omega^(2))^(5) , where omega and omega^(2) are the complex cube roots of unity is

(b) answer any one of the foll.: (i) prove without expanding |[1,omega,omega ^2],[omega ,omega ^2 ,1],[omega ^2,1, omega]|=0 wher w is an imaginary cube root of unity.

If omega is an imaginary cube root of unit,then the value of the expression (1+1/omega)(1+1/omega^2)+(2+1/omega)(2+1/omega^2)+(3+1/omega)(3+1/omega^2) +...+ (n+1/omega)(n+1/omega^2) is

If x=omega-omega^2-2 then , the value of x^4+3x^3+2x^2-11x-6 is (where omega is a imaginary cube root of unity)